20-2x^2=28

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Solution for 20-2x^2=28 equation: 



20-2x^2=28

We move all terms to the left:

20-2x^2-(28)=0

We add all the numbers together, and all the variables

-2x^2-8=0

a = -2; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·(-2)·(-8)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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